document.write( "Question 805610: Find all values of t in the interval [0, 2π] satisfying the given equation: 6 sin 2t + 3 tan 2t = 0. And 6 is under a square root! How to get the answer? Thank you! \n" ); document.write( "

Algebra.Com's Answer #485365 by Alan3354(69443) $\"\"$ $\"About$

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Find all values of t in the interval [0, 2π] satisfying the given equation:
\n" ); document.write( "6 sin 2t + 3 tan 2t = 0. And 6 is under a square root
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\n" ); document.write( " $\"sqrt%286%29%2Asin%282t%29+%2B+3tan%282t%29+=+0\"$
\n" ); document.write( "Use x for 2t
\n" ); document.write( " $\"sqrt%286%29%2Asin%28x%29+%2B+3sin%28x%29%2Fcos%28x%29+=+0\"$
\n" ); document.write( " $\"sin%28x%29%2A%28sqrt%286%29+%2B+3%2Fcos%28x%29%29+=+0\"$
\n" ); document.write( "sin(x) = 0
\n" ); document.write( "x = 2t = 0, pi, 2pi
\n" ); document.write( "t = 0, pi/2, pi
\n" ); document.write( "------------------
\n" ); document.write( " $\"sqrt%286%29+%2B+3%2Fcos%28x%29+=+0\"$
\n" ); document.write( " $\"sqrt%286%29%2Acos%28x%29+%2B+3+=+0\"$
\n" ); document.write( " $\"cos%28x%29+=+-3%2Fsqrt%286%29\"$
\n" ); document.write( "|cos(x)| > 1, no real number solution
\n" ); document.write( " \n" ); document.write( "

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