document.write( "Question 805602: what is 2x=y over 3 minus 4 with work shown \n" ); document.write( "
Algebra.Com's Answer #485353 by MathLover1(20849)\"\" \"About 
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\"2x=y%2F3+-4+\".........here you have both \"x\" and \"y\" first degree variable; so, you have a linear equation\r
\n" ); document.write( "\n" ); document.write( "you can solve it for \"y\" and get \"slope-intercept\" form \"y=mx%2Bb\" where \"m=slope\" and \"b=y-intercept\"\r
\n" ); document.write( "\n" ); document.write( "then you one point that lie on a line and you will need only one more point to graph this line\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B4=y%2F3+\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2A3x%2B4%2A3=y%2A3%2F3+\"\r
\n" ); document.write( "\n" ); document.write( "\"6x%2B12=y+\"\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "\"y=6x%2B12+\"\r
\n" ); document.write( "\n" ); document.write( "so, the slope \"m=6\" and y-intercept is \"b=12\" which means a line crosses \"y-axis\" at point (\"+0+\",\"12\")\r
\n" ); document.write( "\n" ); document.write( "now find one more point; easiest is to find x-intercept, so set \"y=0\" and solve equation for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=6x%2B12+\"\r
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\n" ); document.write( "\n" ); document.write( "\"-12=6x++\"\r
\n" ); document.write( "\n" ); document.write( "\"-12%2F6=x++\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-2++\"\r
\n" ); document.write( "\n" ); document.write( "so,x-intercept is at point (\"+-2+\",\"+0+\")\r
\n" ); document.write( "\n" ); document.write( "plot both points and draw a line through:\r
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