document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=805566>Question 805566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q1.       2^x=1/2\r<BR>\n" );
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document.write( "Q2.    By considering powers of 2, solve the following equation<BR>\n" );
document.write( "          0.25^x=32^(3-x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485314 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485314\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2^x=1/2\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E%28x%29=+2%5E%28-1%29 ALIGN=MIDDLE  ALT=\"2%5E%28x%29=+2%5E%28-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "x=-1\r<BR>\n" );
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document.write( "Q2.    By considering powers of 2, solve the following equation<BR>\n" );
document.write( "          0.25^x=32^(3-x)\r<BR>\n" );
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document.write( "(1/4)^x= 32^(3-x)\r<BR>\n" );
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document.write( "(1/2^2)^x= 2^5(3-x)\r<BR>\n" );
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document.write( "2^-2x = 2^(5(3-x))\r<BR>\n" );
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document.write( "-2x=5(3-x)\r<BR>\n" );
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document.write( "-2x=15-5x\r<BR>\n" );
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document.write( "3x= 15<BR>\n" );
document.write( "x=5 </SPAN>\n" );
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