document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=805562>Question 805562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the age of a father is now 5 times the age of his son. After 18 years, the age of the father will be twice his son's age. <BR>\n" );
document.write( "a). Let x and y be the present age of the father and his son respectively. Set up two equations connecting x and y.<BR>\n" );
document.write( "b). Find their present ages.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485306 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=5y<BR>\n" );
document.write( "x-5y=0..................(1)\r<BR>\n" );
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document.write( "after 18 years<BR>\n" );
document.write( "father's age = (x+18)<BR>\n" );
document.write( "son's age (y+18)\r<BR>\n" );
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document.write( "(x+18)=2(y+18)\r<BR>\n" );
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document.write( "x+18=2y+36<BR>\n" );
document.write( "x-2y=18...............(2)\r<BR>\n" );
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document.write( "subtract (2) from (1)\r<BR>\n" );
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document.write( "-3y=-18\r<BR>\n" );
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document.write( "y=6\r<BR>\n" );
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document.write( "father = 5x = 5*6=30 years<BR>\n" );
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