document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=805560>Question 805560</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When twice the reciprocal of 3 times a number is subtracted from 3 the result is 7 times the reciprocal of 3 times the number. Find the number.\r<BR>\n" );
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document.write( "Can you please help me out? Thanks so much in advance:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485304 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When twice the reciprocal of 3 times a number is subtracted from 3 the result is 7 times the reciprocal of 3 times the number. Find the number.\r<BR>\n" );
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document.write( "number -x<BR>\n" );
document.write( "3 times the number = 3x<BR>\n" );
document.write( "reciprocal = 1/3x<BR>\n" );
document.write( "twice = 2/3x\r<BR>\n" );
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document.write( "3-(2/3x)= 7(1/3x)\r<BR>\n" );
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document.write( "(7/3x)+(2/3x)=3\r<BR>\n" );
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document.write( "9/3x=3<BR>\n" );
document.write( "9x=9<BR>\n" );
document.write( "x=1\r<BR>\n" );
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