document.write( "Question 805507: If g(f(x)) = 9 - 6x, f(x) = 3x - 2, and g(x) = ax + b, then g(x) =\r
\n" ); document.write( "\n" ); document.write( "a) 21 - 18x
\n" ); document.write( "b) 21 - 12x
\n" ); document.write( "c) 10 - 2x
\n" ); document.write( "d) 10 - x
\n" ); document.write( "e) 5 - 2x
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Algebra.Com's Answer #485286 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Use the given f and g to form their composition g(f(x)). Note that the definition for g uses variables, \"a\" and \"b\". \r
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\n" ); document.write( "\n" ); document.write( "\"g%28f%28x%29%29=a%283x-2%29%2Bb\"
\n" ); document.write( "\"3ax-2a%2Bb\"\r
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\n" ); document.write( "\n" ); document.write( "This expression needs to be equal to how the composition was first defined in the given information.
\n" ); document.write( "\"g%28f%28x%29%29=9-6x=3ax-2a%2Bb\"
\n" ); document.write( "\"9-6x=b-2a%2B3ax\"
\n" ); document.write( "Look at the corresponding parts.
\n" ); document.write( "\"9=b-2a\" and \"-6x=3ax\"\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( "The second equation here shows \"-6=3a\", so \"highlight%28a=-2%29\"
\n" ); document.write( "Allowing you to solve for b, in \"9=b-2a\", \"9=b-2%28-2%29\", \"9=b%2B4\", \"highlight%28b=5%29\"\r
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\n" ); document.write( "\n" ); document.write( "NOW, you finish finding g(x).
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