document.write( "Question 805484: I am working on an assignment for \"completing the square\" in quadratic functions. The problem I'm working on is \r
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document.write( "9x^2-12x+4=-3\r
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document.write( "I am struggling with putting this into vertex form.\r
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document.write( "Thank you very much! \n" );
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Algebra.Com's Answer #485268 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! I am working on an assignment for \"completing the square\" in quadratic functions. The problem I'm working on is \r \n" ); document.write( "\n" ); document.write( "9x^2-12x+4=-3 \n" ); document.write( "------------------ \n" ); document.write( "This is a tougher than necessary equation to learn comleting the square, but... \n" ); document.write( "9x^2-12x+4=-3 \n" ); document.write( "Step 1, get the coefficient of x^2 to be 1. Divide by 9 \n" ); document.write( "x^2 - (4/3)x + 4/9 = -1/3 \n" ); document.write( "Put the coefficients terms on the right \n" ); document.write( "x^2 - (4/3)x = -1/3 - 4/9 = -7/9 \n" ); document.write( "Find the c term, where it's ax^2 + bx + c = ... \n" ); document.write( "c = (b/2a)^2 \n" ); document.write( "Since a = 1, it's just (b/2)^2 \n" ); document.write( "b = -4/3 \n" ); document.write( "b/2 = -2/3 \n" ); document.write( "(b/2)^2 = 4/9 \n" ); document.write( "------------ \n" ); document.write( "Add c (= 4/9) to both sides \n" ); document.write( "x^2 - (4/3)x = -7/9 \n" ); document.write( "x^2 - (4/3)x + 4/9 = -7/9 + 4/9 = -3/9 \n" ); document.write( "x^2 - (4/3)x + 4/9 = -3/9 = -1/3 \n" ); document.write( "Now the left side is a \"perfect square.\" \n" ); document.write( " \n" ); document.write( "Take the sqrt of both sides. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "=========== \n" ); document.write( "Not a good teaching example, imo. \n" ); document.write( " |