document.write( "Question 805484: I am working on an assignment for \"completing the square\" in quadratic functions. The problem I'm working on is \r
\n" ); document.write( "\n" ); document.write( "9x^2-12x+4=-3\r
\n" ); document.write( "\n" ); document.write( "I am struggling with putting this into vertex form.\r
\n" ); document.write( "\n" ); document.write( "Thank you very much!
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Algebra.Com's Answer #485268 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
I am working on an assignment for \"completing the square\" in quadratic functions. The problem I'm working on is \r
\n" ); document.write( "\n" ); document.write( "9x^2-12x+4=-3
\n" ); document.write( "------------------
\n" ); document.write( "This is a tougher than necessary equation to learn comleting the square, but...
\n" ); document.write( "9x^2-12x+4=-3
\n" ); document.write( "Step 1, get the coefficient of x^2 to be 1. Divide by 9
\n" ); document.write( "x^2 - (4/3)x + 4/9 = -1/3
\n" ); document.write( "Put the coefficients terms on the right
\n" ); document.write( "x^2 - (4/3)x = -1/3 - 4/9 = -7/9
\n" ); document.write( "Find the c term, where it's ax^2 + bx + c = ...
\n" ); document.write( "c = (b/2a)^2
\n" ); document.write( "Since a = 1, it's just (b/2)^2
\n" ); document.write( "b = -4/3
\n" ); document.write( "b/2 = -2/3
\n" ); document.write( "(b/2)^2 = 4/9
\n" ); document.write( "------------
\n" ); document.write( "Add c (= 4/9) to both sides
\n" ); document.write( "x^2 - (4/3)x = -7/9
\n" ); document.write( "x^2 - (4/3)x + 4/9 = -7/9 + 4/9 = -3/9
\n" ); document.write( "x^2 - (4/3)x + 4/9 = -3/9 = -1/3
\n" ); document.write( "Now the left side is a \"perfect square.\"
\n" ); document.write( "\"%28x+-+2%2F3%29%5E2+=+-1%2F3\"
\n" ); document.write( "Take the sqrt of both sides.
\n" ); document.write( "\"x+-+2%2F3+=+sqrt%28-1%2F3%29+=+i%2Asqrt%283%29%2F3\"
\n" ); document.write( "\"x+=+2%2F3+%2B+i%2Asqrt%283%29%2F3\"
\n" ); document.write( "---------------
\n" ); document.write( "\"x+-+2%2F3+=+sqrt%28-1%2F3%29+=+-i%2Asqrt%283%29%2F3\"
\n" ); document.write( "\"x+=+2%2F3+-+i%2Asqrt%283%29%2F3\"
\n" ); document.write( "===========
\n" ); document.write( "Not a good teaching example, imo.
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