document.write( "Question 805479: The area of a rectangle is 52 ft sq., and the length of the rectangle is 5 ft less than twice the width. Find the dimensions of the rectangle. Please help, I am so confused on this problem. \n" ); document.write( "
Algebra.Com's Answer #485265 by ankor@dixie-net.com(22740)\"\" \"About 
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Write an equation for exactly what it says.
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\n" ); document.write( "The area of a rectangle is 52 ft sq.,
\n" ); document.write( "L * W = 52
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\n" ); document.write( " and the length of the rectangle is 5 ft less than twice the width.
\n" ); document.write( "L = (2W-5)
\n" ); document.write( "In the first equation, replace L with (2W-5), and we have
\n" ); document.write( "(2W-5)*W = 52
\n" ); document.write( "multiply by W inside the brackets
\n" ); document.write( "2W^2 - 5W = 52
\n" ); document.write( "Subtract 52 from both sides, we have a quadratic equation
\n" ); document.write( "2W^2 - 5W - 52 = 0
\n" ); document.write( "You can use the quadratic formula to find w, but this will factor to
\n" ); document.write( "(2W-13)(W+4) = 0
\n" ); document.write( "The positive solution is all we want her
\n" ); document.write( "2W = 13
\n" ); document.write( "W = 13/2
\n" ); document.write( "W = 6.5 ft is the width
\n" ); document.write( "We know
\n" ); document.write( "L = 2W-5
\n" ); document.write( "L = 2(6.5) - 5
\n" ); document.write( "L = 13 - 5
\n" ); document.write( "L = 8 ft is the length
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\n" ); document.write( "Check this by finding the area with these values
\n" ); document.write( "8 * 6.5 = 52
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\n" ); document.write( "Do you understand this now? C\r
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