document.write( "Question 805441: derive the equation for the function with the following characteristics:\r
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document.write( "1. cot x: period 2 pi: phase shift p/4 to the left
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document.write( "2. csc x: period pi : phase shift pi/2 to the right
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document.write( "3. tan x: period pi/2 : vertical shift 3 units up \n" );
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Algebra.Com's Answer #485225 by stanbon(75887) ![]() You can put this solution on YOUR website! derive the equation for the function with the following characteristics: \n" ); document.write( "1. cot x: period 2 pi: phase shift p/4 to the left \n" ); document.write( "Form: y = a*cot[b(x-c)] \n" ); document.write( "Period = 2pi = pi/b; So b = 1/2 \n" ); document.write( "phase shift = c = p/4 \n" ); document.write( "Equation: \n" ); document.write( "y = cot(1/2)(x - (p/4)) \n" ); document.write( "================================= \n" ); document.write( "2. csc x: period pi : phase shift pi/2 to the right \n" ); document.write( "Form: y = a*csc[b(x-c)] \n" ); document.write( "Period = (2pi)/b = pi ; So b = 2 \n" ); document.write( "Phase shift = c = pi/2 \n" ); document.write( "Equation: \n" ); document.write( "y = csc[2(x-(pi/2)) \n" ); document.write( "========================= \n" ); document.write( "3. tan x: period pi/2 : vertical shift 3 units up \n" ); document.write( "Form: y = a*tan[b(x-c)]+d \n" ); document.write( "Period = pi/b = pi/2 ; So b = 2 \n" ); document.write( "Vertical shift = 3 = d \n" ); document.write( "======= \n" ); document.write( "Equation: \n" ); document.write( "y = tan[2x] + 3 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |