document.write( "Question 805441: derive the equation for the function with the following characteristics:\r
\n" ); document.write( "\n" ); document.write( "1. cot x: period 2 pi: phase shift p/4 to the left
\n" ); document.write( "2. csc x: period pi : phase shift pi/2 to the right
\n" ); document.write( "3. tan x: period pi/2 : vertical shift 3 units up
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Algebra.Com's Answer #485225 by stanbon(75887)\"\" \"About 
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derive the equation for the function with the following characteristics:
\n" ); document.write( "1. cot x: period 2 pi: phase shift p/4 to the left
\n" ); document.write( "Form: y = a*cot[b(x-c)]
\n" ); document.write( "Period = 2pi = pi/b; So b = 1/2
\n" ); document.write( "phase shift = c = p/4
\n" ); document.write( "Equation:
\n" ); document.write( "y = cot(1/2)(x - (p/4))
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\n" ); document.write( "2. csc x: period pi : phase shift pi/2 to the right
\n" ); document.write( "Form: y = a*csc[b(x-c)]
\n" ); document.write( "Period = (2pi)/b = pi ; So b = 2
\n" ); document.write( "Phase shift = c = pi/2
\n" ); document.write( "Equation:
\n" ); document.write( "y = csc[2(x-(pi/2))
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\n" ); document.write( "3. tan x: period pi/2 : vertical shift 3 units up
\n" ); document.write( "Form: y = a*tan[b(x-c)]+d
\n" ); document.write( "Period = pi/b = pi/2 ; So b = 2
\n" ); document.write( "Vertical shift = 3 = d
\n" ); document.write( "=======
\n" ); document.write( "Equation:
\n" ); document.write( "y = tan[2x] + 3
\n" ); document.write( "========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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