document.write( "Question 805325: separate 18 into two parts such that twice the sum of their squares is 5 times their product.
\n" ); document.write( "the answers are given by:12and 6. \n" ); document.write( "
Algebra.Com's Answer #485176 by mananth(16946)\"\" \"About 
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let the numbers be x & y\r
\n" ); document.write( "\n" ); document.write( "produst = xy\r
\n" ); document.write( "\n" ); document.write( "sum of squares = x^2+y^2\r
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\n" ); document.write( "\n" ); document.write( "2(x^2+y^2)=5xy\r
\n" ); document.write( "\n" ); document.write( "x^2+y^2=(5/2)xy\r
\n" ); document.write( "\n" ); document.write( "x^2+y^2+2xy = (5/2)xy +2xy\r
\n" ); document.write( "\n" ); document.write( "(x+y)^2=(9/2)xy\r
\n" ); document.write( "\n" ); document.write( "18^2=(9/2)xy\r
\n" ); document.write( "\n" ); document.write( "2*324/9 =xy\r
\n" ); document.write( "\n" ); document.write( "xy=72
\n" ); document.write( "x=72/y\r
\n" ); document.write( "\n" ); document.write( "72/y + y=18
\n" ); document.write( "72+y^2=18y
\n" ); document.write( "y^2-18y+72=0
\n" ); document.write( "y^2-12y-6y+72=0
\n" ); document.write( "(y-12)-6(y-12)=0
\n" ); document.write( "y=6 OR 12\r
\n" ); document.write( "\n" ); document.write( "the lengths are 6 & 12\r
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