document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=805287>Question 805287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sum of three terms of an arithmetic progression is 27 and product of the three terms is 504, find the terms? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485175 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the terms be a,a+d,a+2d\r<BR>\n" );
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document.write( "a+a+d+a+2d= 27<BR>\n" );
document.write( "3a+3d=27<BR>\n" );
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document.write( "a+d=9\r<BR>\n" );
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document.write( "a(a+d)(a+2d)=504<BR>\n" );
document.write( "a+d =9<BR>\n" );
document.write( "a*9*(9+d)=504\r<BR>\n" );
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document.write( "a= 9-d<BR>\n" );
document.write( "(9-d)(9+d)*9=504\r<BR>\n" );
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document.write( "(9+d)(9-d)=504/9<BR>\n" );
document.write( "9^2-d^2=56<BR>\n" );
document.write( "d^2=81-56<BR>\n" );
document.write( "d^2=25\r<BR>\n" );
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document.write( "d=+/-5\r<BR>\n" );
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document.write( "a+d =9\r<BR>\n" );
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document.write( "when d = 5<BR>\n" );
document.write( "a=4<BR>\n" );
document.write( "the numbers are 4,9,15\r<BR>\n" );
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document.write( "The same when you take d=-5\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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