document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=805300>Question 805300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radius of cross-section of a solid cylindrical rod of iron is 50cm the cylinder is melted down and formed into 6 solid spherical balls of the same radius as that of the cylinder the length of the rod(in metres)is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485173 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Radius of cylinder = 50 cm<BR>\n" );
document.write( "length of cylinder = x\r<BR>\n" );
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document.write( "Volume of cylinder = pi r^2*x\r<BR>\n" );
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document.write( "radius of sphere = x<BR>\n" );
document.write( "volume of sphere = 4/3 pi r^3<BR>\n" );
document.write( "6 spheres<BR>\n" );
document.write( "total volume of 6 spheres = 6*(4/3) pi r^3\r<BR>\n" );
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document.write( "8 pir^3\r<BR>\n" );
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document.write( "Volumes are equal\r<BR>\n" );
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document.write( "8 pi r^3= pi r^2 x\r<BR>\n" );
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document.write( "8r = x\r<BR>\n" );
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document.write( "r= 50<BR>\n" );
document.write( "x= 8*50<BR>\n" );
document.write( "400 cm length of rod\r<BR>\n" );
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document.write( " </SPAN>\n" );
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