document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=805322>Question 805322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains, each of length 125 metre, are running in parallel tracks in opposite directions. One train is running in a speed 65 km/hour and they cross each other in 6 seconds. The speed of the other train is  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485171 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to completely cross each other they have to travel 125+125=250 meters\r<BR>\n" );
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document.write( "=0.25 km\r<BR>\n" );
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document.write( "let the train speed be x<BR>\n" );
document.write( "combined speed = 65+x\r<BR>\n" );
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document.write( "6 seconds = 6/3600 = 1/600 hours\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "0.25/(65+x)=1/600\r<BR>\n" );
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document.write( "600*0.25 = 65+x\r<BR>\n" );
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document.write( "150=65+x<BR>\n" );
document.write( "x=150-65<BR>\n" );
document.write( "x=85 mph\r<BR>\n" );
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