document.write( "Question 805262: Person A can paint the neighbors house 2 times as fast as person B. The year A and B worked together, it took them 6 days. how long would it take each to paint the house? \n" ); document.write( "
Algebra.Com's Answer #485148 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Person A can paint the neighbors house 2 times as fast as person B. \n" ); document.write( " The year A and B worked together, it took them 6 days. how long would it take each to paint the house? \n" ); document.write( "Let a = A's time to paint the house \n" ); document.write( "then \n" ); document.write( "2a = B's time to do it \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1; (a painted house): \n" ); document.write( "Each will do a fraction of the job, the two fractions add up to one. \n" ); document.write( " \n" ); document.write( "multiply by 2a, cancel the denominators \n" ); document.write( "2(6) + 6 = 2a \n" ); document.write( "18 = 2a \n" ); document.write( "a = 9 days for A working alone \n" ); document.write( "then \n" ); document.write( "2(9) = 18 days for B to do it. \n" ); document.write( " |