document.write( "Question 805262: Person A can paint the neighbors house 2 times as fast as person B. The year A and B worked together, it took them 6 days. how long would it take each to paint the house? \n" ); document.write( "
Algebra.Com's Answer #485147 by josgarithmetic(39620)\"\" \"About 
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Look at rates according to jobs per time. \"Paint the house\" is the one job and time is in number of days.\r
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\n" ); document.write( "\n" ); document.write( "Given an amount of days, d, agent A works at the rate of 1/d jobs per day and agent B works at the slower rate of 1/(2d) jobs per day.\r
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\n" ); document.write( "\n" ); document.write( "When agents A and B work at the same time, the needed time for 1 job is 6 days.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28r%2At=j%29\"
\n" ); document.write( "r = rate
\n" ); document.write( "t = time in days
\n" ); document.write( "j = how many jobs.\r
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\n" ); document.write( "\n" ); document.write( "This rate for A and B together is \"1%2F%282d%29%2B1%2Fd\".
\n" ); document.write( "We are given the time for their one job, \"t=6\".
\n" ); document.write( "We understand that \"j=1\" for 1 job.\r
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\n" ); document.write( "\n" ); document.write( "The rate is what is unknown because the rate contains variable d, which is what we must solve for.
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\n" ); document.write( "\n" ); document.write( "Solving for d should be uncomplicated. The rate for each of A and B can be computed using d.
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