document.write( "Question 805220: Consider that overall only 30% of new restaurants succeed in the first year of business. However, if a restaurant is opened in a high population density area the probability of success is 60%. If 40% of the new restaurants are in high population density areas and 60% are in low population density areas what is the probability that a new restaurant opened in a low population density area will succeed? \n" ); document.write( "
Algebra.Com's Answer #485141 by edjones(8007)\"\" \"About 
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Let x = the probability that a new restaurant opened in a low population density area will succeed.
\n" ); document.write( "%SLDAR = Percent successful low density area restaurants
\n" ); document.write( "%SHDAR = Percent successful high density area restaurants
\n" ); document.write( "%SLPDAR + %SHDAR = Overall successful new restaurants
\n" ); document.write( ".6x+(.4*.6)=.3
\n" ); document.write( ".6x+.24=.3
\n" ); document.write( ".6x=.06
\n" ); document.write( "x=0.1=10% the probability that a new restaurant opened in a low population density area will succeed.
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