document.write( "Question 805220: Consider that overall only 30% of new restaurants succeed in the first year of business. However, if a restaurant is opened in a high population density area the probability of success is 60%. If 40% of the new restaurants are in high population density areas and 60% are in low population density areas what is the probability that a new restaurant opened in a low population density area will succeed? \n" ); document.write( "
Algebra.Com's Answer #485141 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let x = the probability that a new restaurant opened in a low population density area will succeed. \n" ); document.write( "%SLDAR = Percent successful low density area restaurants \n" ); document.write( "%SHDAR = Percent successful high density area restaurants \n" ); document.write( "%SLPDAR + %SHDAR = Overall successful new restaurants \n" ); document.write( ".6x+(.4*.6)=.3 \n" ); document.write( ".6x+.24=.3 \n" ); document.write( ".6x=.06 \n" ); document.write( "x=0.1=10% the probability that a new restaurant opened in a low population density area will succeed. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |