document.write( "Question 805246: The length of Marshall's poster is 2 times its width. If the perimeter is 72 inches, what is the area of the poster? \n" ); document.write( "

Algebra.Com's Answer #485137 by josmiceli(19441) $\"\"$ $\"About$

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Let perimeter = $\"+P+\"$
\n" ); document.write( "Let width = $\"+w+\"$
\n" ); document.write( "Length is $\"+L+=+2w+\"$
\n" ); document.write( "The formula for perimeter is:
\n" ); document.write( " $\"+P+=+2w+%2B+2L+\"$
\n" ); document.write( " $\"+P+=+2w+%2B+2%2A%282w%29+\"$
\n" ); document.write( " $\"+P+=+2w+%2B+4w+\"$
\n" ); document.write( " $\"+P+=+6w+\"$
\n" ); document.write( "-----------
\n" ); document.write( " $\"+72+=+6w+\"$
\n" ); document.write( " $\"+w+=+72%2F6+\"$
\n" ); document.write( " $\"+w=+12+\"$
\n" ); document.write( "-----------
\n" ); document.write( "Let $\"+A+\"$ = area
\n" ); document.write( " $\"+A+=+L%2Aw+\"$
\n" ); document.write( " $\"+A+=+%282w%29%2Aw+\"$
\n" ); document.write( " $\"+A+=+2w%5E2+\"$
\n" ); document.write( " $\"+A+=+2%2A12%5E2+\"$
\n" ); document.write( " $\"+A+=+2%2A144+\"$
\n" ); document.write( " $\"+A+=+288+\"$ in2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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