document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=805237>Question 805237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water must be evaporated form 340 pounds of a solution that is 3% alcohol to strengthen it to a solution that is 5% alcohol </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485131 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much water must be evaporated form 340 pounds of a solution that is 3% alcohol to strengthen it to a solution that is 5% alcohol<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "water - water = water<BR>\n" );
document.write( "0.97*340 - 1*x = 0.95(340-x)<BR>\n" );
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document.write( "97*340 - 100x = 95*340 - 95x<BR>\n" );
document.write( "5x = 2*340<BR>\n" );
document.write( "x = 2*68 = 136 lbs (amt. of water to evaporate)<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );