document.write( "Question 804971: how do I determine the exact value of sin^2(-5π/6)? \n" ); document.write( "
Algebra.Com's Answer #485045 by lwsshak3(11628)\"\" \"About 
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determine the exact value of sin^2(-5π/6)
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\n" ); document.write( "(-5π/6) is in quadrant III where sin<0
\n" ); document.write( "reference angle = π/6
\n" ); document.write( "sin^2(-5π/6)=sin^2(π/6)=(-1/2)^2=1/4
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