document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=804923>Question 804923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 11 am Mandy begins cycling west averaging 30 mph.  Twenty minutes later Liz leaves from the same point going the same direction averaging 36 mph.  At what time will Liz catch up to Mandy?\r<BR>\n" );
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document.write( "Mandy 30 mph at 11  .5 miles a minute<BR>\n" );
document.write( "Liz 36 mph at 11:20  1.67 miles a minute\r<BR>\n" );
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document.write( "difference 6 mph </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485024 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 11 am Mandy begins cycling west averaging 30 mph.  Twenty minutes later Liz leaves from the same point going the same direction averaging 36 mph.  At what time will Liz catch up to Mandy?<BR>\n" );
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document.write( "In 20 minutes, Mandy is 10 miles away.<BR>\n" );
document.write( "Liz gains on her at 6 mi/hr<BR>\n" );
document.write( "10/6 = 5/3 hours = 1 hr 40 minutes<BR>\n" );
document.write( "11:20 + 1:40 = 1300 hours = 1 PM<BR>\n" );
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