document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68183>Question 68183</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321159365/algebrahomeworkh>Precalculus</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Use synthetic division for the given polynomial<BR>\n" );
document.write( "f(x) = 2x3 -5x2- 4x + 3, find all the solutions if the function is completed. <BR>\n" );
document.write( "a) f(x) =0<BR>\n" );
document.write( "b) f(x+2)=0<BR>\n" );
document.write( "d) f(2x) = 0\r<BR>\n" );
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document.write( "Please show the work.  I have the answer, I just need to confirm I did all of the steps correct.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48499 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use synthetic division for the given polynomial<BR>\n" );
document.write( "f(x) = 2x3 -5x2- 4x + 3, find all the solutions if the function is completed.<BR>\n" );
document.write( "a) f(x) =0<BR>\n" );
document.write( "TEST F(1),F(-1),F(3),F(-3) ETC..<BR>\n" );
document.write( "F(-1)=-2-5+4+3=0..........X=-1 IS A SOLUTION<BR>\n" );
document.write( "-1|2,-5,-4,+3<BR>\n" );
document.write( "..|0,-2,+7,-3<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "...2,-7,+3,0<BR>\n" );
document.write( "2X^2-7X+3=0<BR>\n" );
document.write( "=2X^2-6X-X+3=0<BR>\n" );
document.write( "=2X(X-3)-1(X-3)=0<BR>\n" );
document.write( "(2X-1)(X-3)=0<BR>\n" );
document.write( "HENCE X=1/2 ...OR...3....OR......-1\r<BR>\n" );
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document.write( "b) f(x+2)=0<BR>\n" );
document.write( "PUT Y=X+2.....F(Y)=0....SO....X+2=Y=-1..........OR.......1/2....OR........3<BR>\n" );
document.write( "X=-3..........OR...........-3/2............OR........1<BR>\n" );
document.write( "d) f(2x) = 0<BR>\n" );
document.write( "PUT Y=2X.....F(Y)=0.......2X=Y=-1..........OR........1/2..........OR.......3<BR>\n" );
document.write( "X=-1/2......OR...........1/4..............OR.........3/2\r<BR>\n" );
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document.write( "Please show the work. I have the answer, I just need to confirm I did all of the steps correct.<BR>\n" );
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