document.write( "Question 804801: The length of a rectangle is 3ft more than 5 times its width. If the perimeter is 54ft, what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #484949 by erica65404(394)\"\" \"About 
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L=5W+3
\n" ); document.write( "P=2L+2W
\n" ); document.write( "54=2L+2W
\n" ); document.write( "plug in L
\n" ); document.write( "54=2(5W+3)+2W
\n" ); document.write( "54=10W+6+2W
\n" ); document.write( "54=12W+6
\n" ); document.write( "48=12W
\n" ); document.write( "W=4
\n" ); document.write( "plug W into L=5W+3
\n" ); document.write( "L=5(4)+3
\n" ); document.write( "L=23
\n" ); document.write( "The length is 23ft and the width is 4ft
\n" ); document.write( "
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