document.write( "Question 804801: The length of a rectangle is 3ft more than 5 times its width. If the perimeter is 54ft, what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #484949 by erica65404(394)![]() ![]() You can put this solution on YOUR website! L=5W+3 \n" ); document.write( "P=2L+2W \n" ); document.write( "54=2L+2W \n" ); document.write( "plug in L \n" ); document.write( "54=2(5W+3)+2W \n" ); document.write( "54=10W+6+2W \n" ); document.write( "54=12W+6 \n" ); document.write( "48=12W \n" ); document.write( "W=4 \n" ); document.write( "plug W into L=5W+3 \n" ); document.write( "L=5(4)+3 \n" ); document.write( "L=23 \n" ); document.write( "The length is 23ft and the width is 4ft \n" ); document.write( " |