document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=804790>Question 804790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the inverse of f(x)= 1/3x+2 and graph both  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484944 by </B><A HREF=/tutors/aboutme.mpl?userid=erica65404><B>erica65404(394)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=erica65404><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=erica65404><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to find the inverse, take y=1/3x+2 and switch x and y.<BR>\n" );
document.write( "x=1/3y+2 and now solve for y<BR>\n" );
document.write( "x-2=1/3y<BR>\n" );
document.write( "y=3x-6 is the inverse<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F3%29x%2B2%2C+3x-6%29 ALIGN=MIDDLE  ALT=\"graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F3%29x%2B2%2C+3x-6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );