document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=804723>Question 804723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The larger of two numbers is 2 more than 4 times the smaller. Their sum is 67. FIND THE numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484880 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the smaller and let y be the larger.\r<BR>\n" );
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document.write( "y = 4x + 2  <-- \"The larger of the two numbers is 2 more than 4 times the smaller.\"\r<BR>\n" );
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document.write( "x+y = 67  <--- \"The sum is 67\"\r<BR>\n" );
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document.write( "We have a system of equations, and since we have one of these already solved (equation 1), then we are going to use substitution.\r<BR>\n" );
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document.write( "Therefore I will use y=4x+2  for my 2nd equation and get everything in terms of x.\r<BR>\n" );
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document.write( "x + (4x+2) = 67\r<BR>\n" );
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document.write( "5x + 2 = 67\r<BR>\n" );
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document.write( "5x = 65\r<BR>\n" );
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document.write( "x = 13\r<BR>\n" );
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document.write( "Since x = 13, then   13 + y = 67, so y = 54.\r<BR>\n" );
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document.write( "13, 54. </SPAN>\n" );
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