document.write( "Question 804699: Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 56 feet. \n" ); document.write( "
Algebra.Com's Answer #484871 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
If you spent a little time on the problem instead of wasting your time writing this.
\n" ); document.write( "[The length is______________________feet
\n" ); document.write( "The width is_________________________feet]\r
\n" ); document.write( "\n" ); document.write( "L=1+2W
\n" ); document.write( "56=2W+2L
\n" ); document.write( "56=2W+2*(1+2W)
\n" ); document.write( "56=2W+2+4W
\n" ); document.write( "54=6W
\n" ); document.write( "9=W
\n" ); document.write( "L=1+2*9
\n" ); document.write( "L=19
\n" ); document.write( "check
\n" ); document.write( "56=2*9+2*19
\n" ); document.write( "56=18+38
\n" ); document.write( "56=56
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );