document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=804578>Question 804578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 8 years time Tess will be 5 times as old as her age 8 years ago. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484828 by </B><A HREF=/tutors/aboutme.mpl?userid=thejackal><B>thejackal(72)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thejackal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thejackal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lets call Tess's age today T<BR>\n" );
document.write( "thus, 8 years tess's age was T - 8<BR>\n" );
document.write( "and thus 8 from now (8+T) tess will be 5 times her age 8 years ago (5(T-8))\r<BR>\n" );
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document.write( "so how old is Tess?\r<BR>\n" );
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document.write( "well, we now have a beautiful linear equation with only one unknown\r<BR>\n" );
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document.write( "given as 8+T = 5(T - 8)<BR>\n" );
document.write( "simplify to get 8+T = 5T - 40 which leads to 8 + 40 = 5T - T or 48 = 4T\r<BR>\n" );
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document.write( "i'm sure you can work out T on you own now </SPAN>\n" );
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