document.write( "Question 804477: (Root of 256)^(2x +3) = (1/64)^(x-5)\r
\n" ); document.write( "\n" ); document.write( "(256^1/2)^(2x+3)=(1/64)^(x-5)
\n" ); document.write( "(256)^(x+1/2) \n" ); document.write( "

Algebra.Com's Answer #484751 by erica65404(394) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"sqrt%28256%29%5E%282x%2B3%29=%281%2F64%29%5E%28x-5%29\"$
\n" ); document.write( " $\"16%5E%282x%2B3%29=%281%2F64%29%5E%28x-5%29\"$
\n" ); document.write( " $\"%282%5E4%29%5E%282x%2B3%29=%282%5E%28-6%29%29%5E%28x-5%29\"$
\n" ); document.write( " $\"2%5E%284%282x%2B3%29%29=2%5E%28-6%28x-5%29%29\"$
\n" ); document.write( "log both sides
\n" ); document.write( " $\"4%282x%2B3%29=-6%28x-5%29\"$
\n" ); document.write( " $\"8x%2B12=-6x%2B30\"$
\n" ); document.write( " $\"14x=18\"$
\n" ); document.write( "x=1.29 \n" ); document.write( "

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