document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=804477>Question 804477</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (Root of 256)^(2x +3) = (1/64)^(x-5)\r<BR>\n" );
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document.write( "(256^1/2)^(2x+3)=(1/64)^(x-5)<BR>\n" );
document.write( "(256)^(x+1/2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484750 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (Root of 256)^(2x +3) = (1/64)^(x-5)<BR>\n" );
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document.write( "(sqrt(2^8))^(2x+3) = (2^-6)^(x-5)<BR>\n" );
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document.write( "(2^4)^(2x+3) = 2^(30-6x)<BR>\n" );
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document.write( "2^(8x+12) = 2^(30-6x)<BR>\n" );
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document.write( "8x+12 = 30-6x<BR>\n" );
document.write( "14x = 8<BR>\n" );
document.write( "x = 4/7<BR>\n" );
document.write( "=======================\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "======================= </SPAN>\n" );
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