document.write( "Question 804461: The area of a rectangle is 36 square inches. The perimeter of the rectangle is 36 inches. What are the dimensions of the rectangle to the nearest hundredth of an inch? \n" ); document.write( "
Algebra.Com's Answer #484748 by stanbon(75887)\"\" \"About 
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The area of a rectangle is 36 square inches. The perimeter of the rectangle is 36 inches. What are the dimensions of the rectangle to the nearest hundredth of an inch?
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\n" ); document.write( "Area:: L*W = 36
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\n" ); document.write( "Perimeter:: 2(L+W) = 36
\n" ); document.write( "L + W = 18
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\n" ); document.write( "Substitute for \"L\" and solve for \"W\"::
\n" ); document.write( "(18-W)W = 36
\n" ); document.write( "-W^2 + 18W = 36
\n" ); document.write( "W^2 - 18W + 36 = 0
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\n" ); document.write( "W = [18 +-sqrt(18^2-4*1*36)]/(2)
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\n" ); document.write( "W = [18+-sqrt(180)]/(2)
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\n" ); document.write( "W = (18+6sqrt(5))]/(2)
\n" ); document.write( "W = 15.71 inches
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\n" ); document.write( "Solve for \"L\"::
\n" ); document.write( "L + W = 18
\n" ); document.write( "L + 15.71 = 18
\n" ); document.write( "L = 2.29 inches
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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