document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=804342>Question 804342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Stuck on this algebra problem, and even my dad is kind of confused. Suppose you have a coin collection of nickels and dimes containing 63 coins. If you have $4 total, how many of each type of coin do you have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484708 by </B><A HREF=/tutors/aboutme.mpl?userid=erica65404><B>erica65404(394)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=erica65404><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=erica65404><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=nickels y=dimes<BR>\n" );
document.write( "nickels plus the dimes is equal to 63 coins total.<BR>\n" );
document.write( "x+y=63<BR>\n" );
document.write( "nickels are .05 and dimes are .10.  The total amount you have is $4.00.<BR>\n" );
document.write( ".05x+.10y=4<BR>\n" );
document.write( "to solve for nickels, solve x+y=63 for y<BR>\n" );
document.write( "y=63-x<BR>\n" );
document.write( "now plug into .05x+.10y=4<BR>\n" );
document.write( ".05x+.10(63-x)=4<BR>\n" );
document.write( ".05x+6.3-.10x=4<BR>\n" );
document.write( "-.05x=-2.3<BR>\n" );
document.write( "x=46<BR>\n" );
document.write( "You now know you 46 of the 63 coins are nickels.<BR>\n" );
document.write( "63-46=17<BR>\n" );
document.write( "The answer is 46 nickels and 17 dimes.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );