document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68160>Question 68160</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321356950/algebrahomeworkh>A Graphical Approach to Algebra and Trigonometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line satisfying the given conditions, giving it in slope-intercept form if possible.  Through (-2,0), perpendicular to 8x-3y=7. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48467 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48467\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8X-3Y=7<BR>\n" );
document.write( "-3Y=-8X+7<BR>\n" );
document.write( "Y=8X/3-7/3 THUS THIS LINE HAS A SLOPE OF -8/3.<BR>\n" );
document.write( "THUS A PERPENDICULAR LINE HAS A SLOPE OF 3/8 & PASSING THROUGH (-2,0) IS <BR>\n" );
document.write( "0=3/8*-2+b<BR>\n" );
document.write( "0=-6/8+b<BR>\n" );
document.write( "b=6/8<BR>\n" );
document.write( "b=3/4<BR>\n" );
document.write( "THUS THE EQUATION OF THIS LINE IS<BR>\n" );
document.write( "Y=3/8X+3/4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );