document.write( "Question 804226: Math Question Simple it is ?
\n" ); document.write( "John of height 1.2m is going away from the lamp post at speed of 1.5m/s.
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Algebra.Com's Answer #484667 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "It would be easy, relatively speaking, had you bothered to mention how far away from the pole he was when he started walking. Since you didn't, I have to guess that he was right next to the lamppost when he started moving.\r
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\n" ); document.write( "\n" ); document.write( "At 1.5 m/sec, in 3 sec, he moves 4.5 meters. So after 3 seconds, you have two similar triangles, one that has a leg of 1.2 meters (his height) and another leg of meters (the length of his shadow and ultimately the answer to this problem). The other triangle has a leg that measures 3.9 meters and the other leg is the 4.5 meters he has moved away PLUS the meter length of his shadow.\r
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\n" ); document.write( "\n" ); document.write( "Corresponding sides of similar triangles are proportional, so:\r
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\n" ); document.write( "\n" ); document.write( "Solve for \r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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