document.write( "Question 804226: Math Question Simple it is ?
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document.write( "John of height 1.2m is going away from the lamp post at speed of 1.5m/s.
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document.write( "If the lamp post is 3.9 m above the ground then the length of his shadow after 3 seconds is ?\r
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Algebra.Com's Answer #484667 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It would be easy, relatively speaking, had you bothered to mention how far away from the pole he was when he started walking. Since you didn't, I have to guess that he was right next to the lamppost when he started moving.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 1.5 m/sec, in 3 sec, he moves 4.5 meters. So after 3 seconds, you have two similar triangles, one that has a leg of 1.2 meters (his height) and another leg of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Corresponding sides of similar triangles are proportional, so:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |