document.write( "Question 804030: Find the dimensions of a rectangle whose perimeter is 36 inches and whose length is three times its width \n" ); document.write( "

Algebra.Com's Answer #484574 by erica65404(394) $\"\"$ $\"About$

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$\"P=L%2BL%2BW%2BW\"$
\n" ); document.write( " $\"36=2L%2B2W\"$ The perimeter is 36 inches.
\n" ); document.write( " $\"L=3W\"$ The length is 3 times the width.
\n" ); document.write( "now place $\"L=3W\"$ into $\"36=2L%2B2W\"$ .
\n" ); document.write( " $\"36=2%283W%29%2B2W\"$
\n" ); document.write( " $\"36=8W\"$
\n" ); document.write( " $\"W=4.5\"$
\n" ); document.write( "Now plug 4.5 into $\"36=2L%2B2W\"$ .
\n" ); document.write( " $\"36=2L%2B2%284.5%29\"$
\n" ); document.write( " $\"36=2L%2B9\"$
\n" ); document.write( " $\"27=2L\"$
\n" ); document.write( " $\"L=13.5\"$ \n" ); document.write( "

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