document.write( "Question 803690: Please help me solve this : A chemist can purchase a 10% saline solution in 500 cubic centimeter containers, a 20% saline solution in 500 cubic centimeter containers, and a 50% saline solution in 1,000 cubic centimeter containers. He needs 12,000 cubic centimeters of 30% saline solution. How many containers of each type of solution should he purchase in order to form this solution? \n" ); document.write( "
Algebra.Com's Answer #484568 by ankor@dixie-net.com(22740)\"\" \"About 
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A chemist can purchase a 10% saline solution in 500 cubic centimeter containers, a 20% saline solution in 500 cubic centimeter containers, and a 50% saline solution in 1,000 cubic centimeter containers.
\n" ); document.write( " He needs 12,000 cubic centimeters of 30% saline solution.
\n" ); document.write( " How many containers of each type of solution should he purchase in order to form this solution?
\n" ); document.write( ":
\n" ); document.write( "It will greatly simplify things if we just use the 10% and the 50% solutions
\n" ); document.write( ":
\n" ); document.write( "Let x = amt (in cu/cm) of 50% solution
\n" ); document.write( "the resulting amt is 12000 cu/cm, therefore
\n" ); document.write( "(12000-x) = amt of 10% solution
\n" ); document.write( ":
\n" ); document.write( "A typical mixture equation
\n" ); document.write( ":
\n" ); document.write( ".10(12000-x) .50x = .30(12000)
\n" ); document.write( "1200 - .10x + .50x = 3600
\n" ); document.write( "-.10x + .50x = 3600 - 1200
\n" ); document.write( ".40x = 2400
\n" ); document.write( "x = 2400/.4
\n" ); document.write( "x = 6000 cu/cm of the 50% solution
\n" ); document.write( "then also
\n" ); document.write( "6000 cu/cm of the 10% solution
\n" ); document.write( ":
\n" ); document.write( "The requirement then
\n" ); document.write( "6000/1000 = 6 ea containers of the 50% solution
\n" ); document.write( "and
\n" ); document.write( "6000/500 = 12 ea containers of the 10% solution
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