document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803758>Question 803758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help I'm stuck on a linear equation using the ELIMINATION method.<BR>\n" );
document.write( "The question is as follows:<BR>\n" );
document.write( "2x+3y =7<BR>\n" );
document.write( "3x-2y =4<BR>\n" );
document.write( "Would appreciate any help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484489 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+3y =7<BR>\n" );
document.write( "3x-2y =4<BR>\n" );
document.write( "multiply the first equation by 2 and multiply the second equation by 3<BR>\n" );
document.write( "4x+6y =14<BR>\n" );
document.write( "9x-6y =12<BR>\n" );
document.write( "add the resulting equations <BR>\n" );
document.write( "13x =26<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( "substitute for x in first equation<BR>\n" );
document.write( "2*2 +3y = 7<BR>\n" );
document.write( "3y = 3<BR>\n" );
document.write( "y = 1<BR>\n" );
document.write( "check the answers by substituting the second equation<BR>\n" );
document.write( "3*2 -2*1 =4<BR>\n" );
document.write( "6 -2 = 4<BR>\n" );
document.write( "4 =4<BR>\n" );
document.write( "answers check<BR>\n" );
document.write( "x = 2, y = 1\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );