document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803739>Question 803739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the present age of father and his daughter  is 42 years  7 years later the  father will be 3 times old then the daughter the present age of the father is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484467 by </B><A HREF=/tutors/aboutme.mpl?userid=erica65404><B>erica65404(394)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=erica65404><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=erica65404><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484467\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You know that the age of the daughter plus the age of the father is 42 years.  You will use the equation x+y=42 (x=father y=daughter).  When its 7 years later and the father will be 3 times the age of his daughter. Both the father and daughter will have aged 7 years so you would add 14 to 42 and now your equation will be x+y=56.  you also need an equation to show that the father will be 3 times the age of his daughter.  You would use 3y=x. now to figure out the fathers age you would need to plug 3y=x into x+y=56.  3y+y=56 we will use this to find the daughters age first.  You will get y=14.  The father will be 3 times the age of his daughter.  You can now plug y=14 into 3y=x to find what the fathers age will be.  You now know the fathers age will be 42 in 7 years.  Since it is present day, simply subtract 7 from 42 to find his current age.  The father is 35 years old. </SPAN>\n" );
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