document.write( "Question 803720: A boats start To cross a river upstream at an angle of 140 deg to the flaw of the river the boat moves directly across the river at 10m/s as a result of combined effect of the velocity of the stream and the velocity of the boat. Calculate
\n" ); document.write( "(a) the velocity of the stream.
\n" ); document.write( "(b)the velocity of the boat in still in water.
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Algebra.Com's Answer #484462 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
You may be able to draw this picture:\r
\n" ); document.write( "\n" ); document.write( "Horizontal axis, current of river toward the right; vertical axis, upward is \"accross\" the river straight up.\r
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\n" ); document.write( "\n" ); document.write( "The boat is trying to go into quadrant 4, so that direction of the boat vector is 140 degrees, using \"to the right...\" as the reference direction, the positive x axis. The river vector is just toward the right, no angle, since angle 0 is unrotated and toward the right.\r
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\n" ); document.write( "\n" ); document.write( "b for the boat's magnitude, r for the river's magnitude.
\n" ); document.write( "The boat vector is \"b%2Acos%28140%29%2Bb%2Asin%28140%29\"
\n" ); document.write( "The river vector is \"r%2Acos%280%29%2Br%2Asin%280%29\"
\n" ); document.write( "The sum of the vectors for b and r is \"10%2A%28cos%2890%29%2Bsin%2890%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Adding the components will give you two equations.
\n" ); document.write( "\"b%2Acos%28140%29%2Br%2Acos%280%29=10%2Acos%2890%29\" and \"b%2Asin%28140%29%2Br%2Asin%280%29=10%2Asin%2890%29\"
\n" ); document.write( "\"b%28-0.766%29%2Br=10%2A0\" and \"b%2A%280.643%29%2Br%2A0=10%2A1\"
\n" ); document.write( "\"-0.766b%2Br=0\" and \"0.643b=10\"
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\n" ); document.write( "\"r=0.766b\" and \"b=10%2F%280.643%29\"\r
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\n" ); document.write( "\n" ); document.write( "Second part simplified is then \"highlight%28b=15.55%29\", and therefore \"r=0.766%2A15.55=highlight%2811.91%29\".
\n" ); document.write( "If you prefer for proper accuracy, \"b=16\" and \"r=12\".
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