document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803724>Question 803724</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I am 13 and my dad is 41 in how many years will he be exactly twice my age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484457 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> after x years you will be 1/2 dad's age\r<BR>\n" );
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document.write( "your age after x years\r<BR>\n" );
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document.write( "13+x\r<BR>\n" );
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document.write( "Dad's age after x years<BR>\n" );
document.write( "41+x\r<BR>\n" );
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document.write( "13+x= 1/2(41+x)\r<BR>\n" );
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document.write( "2(13+x)=41+x\r<BR>\n" );
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document.write( "26+2x=41+x\r<BR>\n" );
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document.write( "2x-x=41-26<BR>\n" );
document.write( "x=15\r<BR>\n" );
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document.write( "you will be 28 he will be 56 </SPAN>\n" );
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