document.write( "Question 803721: A real estate firm invests $100,000 in two ways. The first portion is invested with an annual return of 8%. The rest is invested for an annual return of 5%. The firm wants an annual income of $6800 from the investments. How much should be put into each investment. \n" ); document.write( "
Algebra.Com's Answer #484453 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 8.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 5.00% per annum ------------ Amount invested = y \n" ); document.write( " 100000 \n" ); document.write( "Interest----- 6800.00 \n" ); document.write( " \n" ); document.write( "Part I 8.00% per annum ---x \n" ); document.write( "Part II 5.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 100000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "8.00% x + 5.00% y= 6800 \n" ); document.write( "Multiply by 100 \n" ); document.write( "8 x + 5 y= 680000.00 --------2 \n" ); document.write( "Multiply (1) by -8 \n" ); document.write( "we get \n" ); document.write( "-8 x -8 y= -800000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -3 y= -120000 \n" ); document.write( "divide by -3 \n" ); document.write( " y = 40000 - x) \n" ); document.write( "Part I 8.00% $ 60000 \n" ); document.write( "Part II 5.00% $ 40000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "60000 --------- 8.00% ------- 4800.00 \n" ); document.write( "40000 ------------- 5.00% ------- 2000.00 \n" ); document.write( "Total -------------------- 6800.00 \n" ); document.write( " \n" ); document.write( " |