document.write( "Question 803721: A real estate firm invests $100,000 in two ways. The first portion is invested with an annual return of 8%. The rest is invested for an annual return of 5%. The firm wants an annual income of $6800 from the investments. How much should be put into each investment. \n" ); document.write( "
Algebra.Com's Answer #484453 by mananth(16946)\"\" \"About 
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Part I 8.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 5.00% per annum ------------ Amount invested = y
\n" ); document.write( " 100000
\n" ); document.write( "Interest----- 6800.00
\n" ); document.write( "
\n" ); document.write( "Part I 8.00% per annum ---x
\n" ); document.write( "Part II 5.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 100000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "8.00% x + 5.00% y= 6800
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8 x + 5 y= 680000.00 --------2
\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
\n" ); document.write( "-8 x -8 y= -800000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -3 y= -120000
\n" ); document.write( "divide by -3
\n" ); document.write( " y = 40000 - x)
\n" ); document.write( "Part I 8.00% $ 60000
\n" ); document.write( "Part II 5.00% $ 40000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "60000 --------- 8.00% ------- 4800.00
\n" ); document.write( "40000 ------------- 5.00% ------- 2000.00
\n" ); document.write( "Total -------------------- 6800.00
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