document.write( "Question 803654: the speed of a river's current is 4mph. a boat travels 40 miles upstream at a constant rate of speed. if the speed has been 9mph faster, the trip would have taken 1 hour less time. what is the boat's speed in still water? \n" ); document.write( "
Algebra.Com's Answer #484450 by mananth(16946)\"\" \"About 
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the speed of a river's current is 4mph. a boat travels 40 miles upstream at a constant rate of speed. if the speed has been 9mph faster, the trip would have taken 1 hour less time. what is the boat's speed in still water?\r
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\n" ); document.write( "\n" ); document.write( "current speed = 4 mph
\n" ); document.write( "boat speed in still water =x\r
\n" ); document.write( "\n" ); document.write( "upstream speed = x-4\r
\n" ); document.write( "\n" ); document.write( "t=d/r
\n" ); document.write( "40/(x-4) hours\r
\n" ); document.write( "\n" ); document.write( "--
\n" ); document.write( "If spee}}}d was increased by 9 mph\r
\n" ); document.write( "\n" ); document.write( "speed = (x-4+9) = x+5 \r
\n" ); document.write( "\n" ); document.write( "t= 40/(x+5)\r
\n" ); document.write( "\n" ); document.write( "difference in time = 1 hour\r
\n" ); document.write( "\n" ); document.write( "\"40%2F%28x-4%29+-+40%2F%28x%2B5%29+=1\"\r
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\n" ); document.write( "\n" ); document.write( "40(x+5)-40(x-4) =(x-4)(x+5)*1\r
\n" ); document.write( "\n" ); document.write( "40x+200-40x+160=x^2+x-20\r
\n" ); document.write( "\n" ); document.write( "x^2+x-380=0\r
\n" ); document.write( "\n" ); document.write( "x^2+20x-19x-380=0\r
\n" ); document.write( "\n" ); document.write( "x(x+20)-19(x+20)=0\r
\n" ); document.write( "\n" ); document.write( "(x+20)(x-19)=0\r
\n" ); document.write( "\n" ); document.write( "x=-20 OR 19\r
\n" ); document.write( "\n" ); document.write( "ignore negative\r
\n" ); document.write( "\n" ); document.write( "speed in still water = 19mph
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