document.write( "Question 803659: What quantity of a 50% acid solution must be mixed with a 20% solution to produce 150mL of a 40% solution?
\n" ); document.write( "A. 90mL
\n" ); document.write( "B. 60mL
\n" ); document.write( "C. 50mL
\n" ); document.write( "D. 100mL
\n" ); document.write( "E. 120mL\r
\n" ); document.write( "\n" ); document.write( "Show work
\n" ); document.write( "

Algebra.Com's Answer #484446 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
percent ---------------- quantity
\n" ); document.write( "acid solution I 50.00% ---------------- x ml
\n" ); document.write( "acid solution II 20.00% ------ 150 - x ml
\n" ); document.write( "Mixture 40.00% ---------------- 150
\n" ); document.write( "Total 150 ml
\n" ); document.write( "50.00% x + 20.00% ( 150 - x ) = 40.00% * 150
\n" ); document.write( "50 x + 20 ( 150 - x ) = 6000
\n" ); document.write( "50 x + 3000 - 20 x = 6000
\n" ); document.write( "50 x - 20 x = 6000 - -3000
\n" ); document.write( "30 x = 3000
\n" ); document.write( "/ 30
\n" ); document.write( " x = 100 ml 50.00% acid solution I
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" ); document.write( "
\n" );