document.write( "Question 803659: What quantity of a 50% acid solution must be mixed with a 20% solution to produce 150mL of a 40% solution?
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document.write( "A. 90mL
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document.write( "B. 60mL
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document.write( "C. 50mL
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document.write( "D. 100mL
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document.write( "E. 120mL\r
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document.write( "Show work \n" );
document.write( "
Algebra.Com's Answer #484446 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "acid solution I 50.00% ---------------- x ml \n" ); document.write( "acid solution II 20.00% ------ 150 - x ml \n" ); document.write( "Mixture 40.00% ---------------- 150 \n" ); document.write( "Total 150 ml \n" ); document.write( "50.00% x + 20.00% ( 150 - x ) = 40.00% * 150 \n" ); document.write( "50 x + 20 ( 150 - x ) = 6000 \n" ); document.write( "50 x + 3000 - 20 x = 6000 \n" ); document.write( "50 x - 20 x = 6000 - -3000 \n" ); document.write( "30 x = 3000 \n" ); document.write( "/ 30 \n" ); document.write( " x = 100 ml 50.00% acid solution I \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |