document.write( "Question 803697: Traveling for 3 hours into a steady headwind, a plane flies 1650 miles. The pilot determines that flying with the same wind for 2 hours, he could make a trip of 1300 miles. Find the speed of the plane and the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #484444 by mananth(16946)\"\" \"About 
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Plane speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 3 hours
\n" ); document.write( "with wind 2 hours
\n" ); document.write( "
\n" ); document.write( "Distance against 1650 miles distance with 1300 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "1650.00 / ( x - y )= 3.00
\n" ); document.write( "3.00 ( x - y ) = 2.00
\n" ); document.write( "3.00 x - 3.00 y = 1650.00 ....................1
\n" ); document.write( "
\n" ); document.write( "1300.00 / ( x + y )= 2.00
\n" ); document.write( "2.00 ( x + y ) = 1300.00
\n" ); document.write( "2.00 x + 2.00 y = 1300.00 ...............2
\n" ); document.write( "Multiply (1) by 2.00
\n" ); document.write( "Multiply (2) by 3.00
\n" ); document.write( "we get
\n" ); document.write( "6.00 x + -6.00 y = 3300.00
\n" ); document.write( "6.00 x + 6.00 y = 3900.00
\n" ); document.write( "12.00 x = 7200.00
\n" ); document.write( "/ 12.00
\n" ); document.write( "x = 600.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "3.00 x -3.00 y = 1650.00
\n" ); document.write( "1800.00 -3.00 -1800.00 = 1650.00
\n" ); document.write( "-3.00 y = 1650.00
\n" ); document.write( "-3.00 y = -150.00 mph
\n" ); document.write( " y = 50.00
\n" ); document.write( "Plane speed 600.00 mph
\n" ); document.write( "wind speed 50.00 mph
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
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