document.write( "Question 803420: we have an unknown number of coin.If you make 77 strings of them, you are 50 coins short, but if you make 78 strings , it is exact.how many coins are there?
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document.write( "[hint:use diophantine equation] \n" );
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Algebra.Com's Answer #484428 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Let n be the answer.\r\n" ); document.write( " \n" ); document.write( "if you make 78 strings , it is exact. \n" ); document.write( " \r\n" ); document.write( "So n is a multiple of 78, and therefore \r\n" ); document.write( "\r\n" ); document.write( "n = 78p, for some natural number q\r\n" ); document.write( " \n" ); document.write( "If you make 77 strings of them, you are 50 coins short \n" ); document.write( " \r\n" ); document.write( "So if 50 is added to n, the result is a multiple of 77\r\n" ); document.write( "\r\n" ); document.write( "Therefore \r\n" ); document.write( "\r\n" ); document.write( " n + 50 = 77q for some integer\r\n" ); document.write( "\r\n" ); document.write( "Substitute 78p for n\r\n" ); document.write( "\r\n" ); document.write( "(1) 78p + 50 = 77q\r\n" ); document.write( "\r\n" ); document.write( "The smaller coefficient of a letter in absolute value is 77\r\n" ); document.write( "\r\n" ); document.write( "So we rewrite 78 and 50 in terms of their nearest multiples of 77\r\n" ); document.write( "We rewrite 78 as 77+1 and 50 as 77-27\r\n" ); document.write( "\r\n" ); document.write( " (77+1)p + 77-27 = 77q\r\n" ); document.write( "\r\n" ); document.write( "77p + p + 77 - 27 = 77q\r\n" ); document.write( "\r\n" ); document.write( "Divide through by 77\r\n" ); document.write( "\r\n" ); document.write( " p +\n" ); document.write( " |