document.write( "Question 803529: I think I solved this correctly, but just wanted to check:\r
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document.write( "9y+3x=18; -3y-x=-6\r
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document.write( "9y=18-3x
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document.write( "y=2-1/3x\r
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document.write( "Substitution for -3y-x=-6
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document.write( "-3(2-1/3x)-x=-6
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document.write( "-6-x-x=-6
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document.write( "-6-2x=-6
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document.write( "x=6\r
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document.write( "9y+3(6)=18
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document.write( "9y=0
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document.write( "y=0
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document.write( "We are supposed to solve for either variable and use the solution to determine the second variable. \r
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document.write( "I got x=6, y=0, but am unsure if this is correct. \n" );
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Algebra.Com's Answer #484400 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! you are correct! \n" ); document.write( "best way to check your answers is to substitute values for x and y in the original equations \n" ); document.write( "x = 6, y = 0 \n" ); document.write( "9*0 +3*6 = 18 \n" ); document.write( "18 = 18 \n" ); document.write( "answers in equation 1 \n" ); document.write( "-3y -x = -6 \n" ); document.write( "-3*0 -6 = -6 \n" ); document.write( "-6 = -6 \n" ); document.write( "answers check in equation 2 \n" ); document.write( " \n" ); document.write( " |