document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803529>Question 803529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I think I solved this correctly, but just wanted to check:\r<BR>\n" );
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document.write( "9y+3x=18; -3y-x=-6\r<BR>\n" );
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document.write( "9y=18-3x<BR>\n" );
document.write( "y=2-1/3x\r<BR>\n" );
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document.write( "Substitution for -3y-x=-6<BR>\n" );
document.write( "-3(2-1/3x)-x=-6<BR>\n" );
document.write( "-6-x-x=-6<BR>\n" );
document.write( "-6-2x=-6<BR>\n" );
document.write( "x=6\r<BR>\n" );
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document.write( "9y+3(6)=18<BR>\n" );
document.write( "9y=0<BR>\n" );
document.write( "y=0<BR>\n" );
document.write( "We are supposed to solve for either variable and use the solution to determine the second variable. \r<BR>\n" );
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document.write( "I got x=6, y=0, but am unsure if this is correct.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484397 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9y+3x=18 --> x + 3y = 6<BR>\n" );
document.write( "-3y-x=-6 --> x + 3y = 6<BR>\n" );
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document.write( "It's the same eqn twice<BR>\n" );
document.write( "--> no unique solution, an infinite number of solutions.<BR>\n" );
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