document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803496>Question 803496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve using the substitution method\r<BR>\n" );
document.write( "\n" );
document.write( "1/3x+1/5y=7, 1/6x-2/5y=-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484391 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/3x+1/5y=7<BR>\n" );
document.write( "1/6x-2/5y=-4 times 2 --> x/3 - 4y/5 = -8 --> x/3 = 4y/5 - 8<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "x/3 + y/5 = 7<BR>\n" );
document.write( "sub for x/3<BR>\n" );
document.write( "(4y/5 - 8) + y/5 = 7<BR>\n" );
document.write( "4y - 40 + y = 35<BR>\n" );
document.write( "5y = 75<BR>\n" );
document.write( "y = 15<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "x/3 + y/5 = 7<BR>\n" );
document.write( "x/3 + 3 = 7<BR>\n" );
document.write( "x/3 = 4<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );