document.write( "Question 803468: Pure acid is to be added to a 5% acid solution to obtain 95L of 45% solution. What amounts of each should she use? \n" ); document.write( "
Algebra.Com's Answer #484369 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Pure acid is to be added to a 5% acid solution to obtain 95L of 45% solution. What amounts of each should she use? \n" ); document.write( "---------------------- \n" ); document.write( "100x + 5(95-x) = 45*95 \n" ); document.write( "95x + 475 = 4275 \n" ); document.write( "x = 40 liters of 100% acid \n" ); document.write( " \n" ); document.write( " |