document.write( "Question 803468: Pure acid is to be added to a 5% acid solution to obtain 95L of 45% solution. What amounts of each should she use? \n" ); document.write( "
Algebra.Com's Answer #484369 by Alan3354(69443)\"\" \"About 
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Pure acid is to be added to a 5% acid solution to obtain 95L of 45% solution. What amounts of each should she use?
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\n" ); document.write( "100x + 5(95-x) = 45*95
\n" ); document.write( "95x + 475 = 4275
\n" ); document.write( "x = 40 liters of 100% acid
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