document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803390>Question 803390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question - Restaurant records show that the total number of high quality disposable napkins used each week in their city premises follows a normal distribution with a mean of 850 napkins with a standard deviation of 24.0 napkins.\r<BR>\n" );
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document.write( "a)The restaurant manager wants to determine how many napkins to have at the beginning of the week so that there is at least a 95% chance that the restaurant will not run out. Calculate the minimum number of napkins required.  Explain your reasoning.\r<BR>\n" );
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document.write( "b)The restaurant manager now wants to determine how many napkins to have at the beginning of the week so that there is at least a 99% chance that all the napkins will be used. Calculate the maximum number of napkins the restaurant should have. Explain your reasoning.\r<BR>\n" );
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document.write( "Please email me. Thank you.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484352 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to solve these two questions, we use the z-value associated with 95% and 99% probabilities to determine the value of x<BR>\n" );
document.write( "a) consult z-value for 95%, which is 1.65<BR>\n" );
document.write( "now we can use the z-value calculation for 95%<BR>\n" );
document.write( "1.65 = (x -850) / 24<BR>\n" );
document.write( "39.6 = x -850<BR>\n" );
document.write( "x = 889.6 = 890 napkins<BR>\n" );
document.write( "b) 2.33 = (x -850) / 24<BR>\n" );
document.write( "55.9 = x -850<BR>\n" );
document.write( "x = 905.9 = 906<BR>\n" );
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