document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803327>Question 803327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 20 ft pole is supported by two wires that extend from the top of the pole to points that are 15 feet from the base of the pole. find the total length of the two wires? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484340 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28340%2C240%2C-17%2C17%2C-2%2C22%2C%0D%0Aline%28-17%2C0%2C17%2C0%29%2Crectangle%28-0.5%2C0%2C0.5%2C20%29%2C%0D%0Aline%28-15.5%2C0%2C-0.5%2C20%29%2Cline%2815.5%2C0%2C0.5%2C20%29%2C%0D%0Alocate%287%2C1.5%2C15%29%2Clocate%280.6%2C11%2C20%29%2C%0D%0Arectangle%280.5%2C0%2C1.5%2C1%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > There are two right triangles formed by the horizontal ground, the sides of the pole and the wire.<BR>\n" );
document.write( "Each triangle has leg lengths of 15 feet and 20 feet.<BR>\n" );
document.write( "You can use the Pythagorean theorem to calculate the length of the hypotenuse, and that would be the half of the wire length used to one side of the pole.<BR>\n" );
document.write( "I don't like those calculations, so I will use a similar triangle that I know and love.<BR>\n" );
document.write( "Those large triangles are scaled-up larger cousins (similar) to the 3:4:5 right triangle that teacher like to use in problems:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28100%2C100%2C-1%2C4%2C-0.5%2C4.5%2C%0D%0Atriangle%280%2C0%2C3%2C0%2C0%2C4%29%2Crectangle%280%2C0%2C0.3%2C0.3%29%2C%0D%0Alocate%281.3%2C0.7%2C3%29%2Clocate%280.1%2C2.2%2C4%29%2Clocate%281.7%2C2.4%2C5%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > In the large triangles, all lengths are 5 times larger, so the hypotenuse measures <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2A5=25 ALIGN=MIDDLE  ALT=\"5%2A5=25\"   DISABLED_style= \"max-width:90%; height:auto;\" > feet, and the total length of wire is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%2850feet%29 ALIGN=MIDDLE  ALT=\"highlight%2850feet%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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