document.write( "Question 803385: The area of a rectangle is x^2-x-12 square units. If the length is (x+3) units , then what is the perimeter of the rectangle \n" ); document.write( "
Algebra.Com's Answer #484333 by mananth(16946)\"\" \"About 
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L * W\r
\n" ); document.write( "\n" ); document.write( "area = x^2-x-12\r
\n" ); document.write( "\n" ); document.write( "length = x+3\r
\n" ); document.write( "\n" ); document.write( "(x^2-x-12)/(x+3)\r
\n" ); document.write( "\n" ); document.write( "(x-4)(x+3)/(x+3)\r
\n" ); document.write( "\n" ); document.write( "= x+4 units is the width
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